What are the solutions to the equation x^2+x=132 ?

The solutions to the equation x^2+x=132 are x=11,x=-12

Find the zeros of x^2+x=132

The zeros of x^2+x=132 are x=11,x=-12

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x^{2} + x = 132

x = 11, x = - 12

Solution steps

x^{2} + x = 132

Move

132

to the left side

x^{2} + x - 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 132 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 132) = 23

x_{1, 2} = \frac{- 1 \pm 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 23}{2 \cdot 1}, x_{2} = \frac{- 1 - 23}{2 \cdot 1}

x = \frac{- 1 + 23}{2 \cdot 1} : 11

x = \frac{- 1 - 23}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 11, x = - 12

74 y - 8 - 78 y = - 4 y - 8

\frac{4}{7} (\frac{2}{3})^{2} + \frac{8}{9}

\frac{a ^{3} \cdot b ^{4} \cdot 5 ^{4}}{b ^{2} \cdot 5}

(y^{2})^{5} \cdot y^{8}

6 ∣ 5 x - 7 ∣ = 3

What are the solutions to the equation x^2+x=132 ?
The solutions to the equation x^2+x=132 are x=11,x=-12
Find the zeros of x^2+x=132
The zeros of x^2+x=132 are x=11,x=-12