What is factor ((7-4y)/3)^2-4y^2-9 ?

The solution to factor ((7-4y)/3)^2-4y^2-9 is -((10y-7)(2y+7))/9-9

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factor ((7-4y)/3)^2-4y^2-9

factor

(\frac{7 - 4 y}{3})^{2} - 4 y^{2} - 9

- \frac{( 10 y - 7 ) ( 2 y + 7 )}{9} - 9

Solution steps

(\frac{7 - 4 y}{3})^{2} - 4 y^{2} - 9

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( - 4 y + 7 ) ^{2}}{3 ^{2}} - 4 y^{2} - 9

Combine the fractions

\frac{( - 4 y + 7 ) ^{2}}{3 ^{2}} - 4 y^{2} : \frac{- ( 10 y - 7 ) ( 2 y + 7 )}{9}

= \frac{- ( 10 y - 7 ) ( 2 y + 7 )}{9} - 9

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{( 10 y - 7 ) ( 2 y + 7 )}{9} - 9

x^{3} + 16 x^{2} + 64 x

2 ∣ x ∣ = 4

5 \cdot 9.8

21 a^{3} b^{3} - 14 a^{2} b^{2} + 2 8^{3} b

6 x + 3 < 21

What is factor ((7-4y)/3)^2-4y^2-9 ?
The solution to factor ((7-4y)/3)^2-4y^2-9 is -((10y-7)(2y+7))/9-9