What are the solutions to the equation 5b^2-11b=12 ?

The solutions to the equation 5b^2-11b=12 are b=3,b=-4/5

Find the zeros of 5b^2-11b=12

The zeros of 5b^2-11b=12 are b=3,b=-4/5

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5 b^{2} - 11 b = 12

b = 3, b = - \frac{4}{5}

Decimal Notation

b = 3, b = - 0.8

Solution steps

5 b^{2} - 11 b = 12

Move

12

to the left side

5 b^{2} - 11 b - 12 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 12) = 19

b_{1, 2} = \frac{- ( - 11 ) \pm 19}{2 \cdot 5}

Separate the solutions

b_{1} = \frac{- ( - 11 ) + 19}{2 \cdot 5}, b_{2} = \frac{- ( - 11 ) - 19}{2 \cdot 5}

b = \frac{- ( - 11 ) + 19}{2 \cdot 5} : 3

b = \frac{- ( - 11 ) - 19}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

b = 3, b = - \frac{4}{5}

\frac{5}{4} + 1

2 x^{2} + 10 x + 8

t^{2} - 6 t - 16 = 0

211 + 4

14 w^{3} + 7 w^{2} - 46 w - 23

What are the solutions to the equation 5b^2-11b=12 ?
The solutions to the equation 5b^2-11b=12 are b=3,b=-4/5
Find the zeros of 5b^2-11b=12
The zeros of 5b^2-11b=12 are b=3,b=-4/5