What are the solutions to the equation p^2+5p-14=0 ?

The solutions to the equation p^2+5p-14=0 are p=2,p=-7

Find the zeros of p^2+5p-14=0

The zeros of p^2+5p-14=0 are p=2,p=-7

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p^{2} + 5 p - 14 = 0

p = 2, p = - 7

Solution steps

p^{2} + 5 p - 14 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

p_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 5 + 9}{2 \cdot 1}, p_{2} = \frac{- 5 - 9}{2 \cdot 1}

p = \frac{- 5 + 9}{2 \cdot 1} : 2

p = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

p = 2, p = - 7

\frac{1 + a ^{3}}{1 + a}

2 x^{2} + 13 x = 7

(\frac{1}{x - 1})^{2}

(x - (2 - 5 i)) (x - (2 + 5 i))

3 - \frac{5}{3}

What are the solutions to the equation p^2+5p-14=0 ?
The solutions to the equation p^2+5p-14=0 are p=2,p=-7
Find the zeros of p^2+5p-14=0
The zeros of p^2+5p-14=0 are p=2,p=-7