What is factor 4y^2+36y+81 ?

The solution to factor 4y^2+36y+81 is (2y+9)^2

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factor 4y^2+36y+81

factor

4 y^{2} + 36 y + 81

(2 y + 9)^{2}

Solution steps

4 y^{2} + 36 y + 81

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 y^{2} = (2 y)^{2}

81 = 9^{2}

36 y = 2 \cdot 2 y \cdot 9

= (2 y)^{2} + 2 \cdot 2 y \cdot 9 + 9^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 y)^{2} + 2 \cdot 2 y \cdot 9 + 9^{2} = (2 y + 9)^{2}

= (2 y + 9)^{2}

\frac{1}{27} = 3^{- 3}

(4 p^{4})^{2}

\frac{( 99.15 - 98.411 )}{99.15} 100

5 aπ (5 a + 17 a) = 360 π

\frac{8}{17}