What are the solutions to the equation x^2+22x+121=0 ?

The solutions to the equation x^2+22x+121=0 are x=-11

Find the zeros of x^2+22x+121=0

The zeros of x^2+22x+121=0 are x=-11

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x^{2} + 22 x + 121 = 0

x = - 11

Solution steps

x^{2} + 22 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 121}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 121 = 0

x_{1, 2} = \frac{- 22 \pm 0}{2 \cdot 1}

x = \frac{- 22}{2 \cdot 1}

\frac{- 22}{2 \cdot 1} = - 11

x = - 11

The solution to the quadratic equation is:

x = - 11

3^{12}

∣ 2.3 - 0.6 x ∣ = 2

x - 2 \geq 21

- 4 < x < 4

a = 11.84 + 0.015 \cdot 680

What are the solutions to the equation x^2+22x+121=0 ?
The solutions to the equation x^2+22x+121=0 are x=-11
Find the zeros of x^2+22x+121=0
The zeros of x^2+22x+121=0 are x=-11