What are the solutions to the equation (x+3)(x+2)=x+13 ?

The solutions to the equation (x+3)(x+2)=x+13 are x=-2+sqrt(11),x=-2-sqrt(11)

Find the zeros of (x+3)(x+2)=x+13

The zeros of (x+3)(x+2)=x+13 are x=-2+sqrt(11),x=-2-sqrt(11)

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(x + 3) (x + 2) = x + 13

x = - 2 + 11, x = - 2 - 11

Decimal Notation

x = 1.31662 \dots, x = - 5.31662 \dots

Solution steps

(x + 3) (x + 2) = x + 13

Expand

(x + 3) (x + 2) : x^{2} + 5 x + 6

x^{2} + 5 x + 6 = x + 13

Move

13

to the left side

x^{2} + 5 x - 7 = x

Move

x

to the left side

x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 7) = 211

x_{1, 2} = \frac{- 4 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 11}{2 \cdot 1}

x = \frac{- 4 + 2 11}{2 \cdot 1} : - 2 + 11

x = \frac{- 4 - 2 11}{2 \cdot 1} : - 2 - 11

The solutions to the quadratic equation are:

x = - 2 + 11, x = - 2 - 11

\frac{a + 4}{8} + \frac{1 - 3 a}{12}

(x - 1)^{2} < (x + 9)^{2}

- 36 x (- 9 x^{2} + 25) > 0

8 + 9 ∣ 5 m - 7 ∣ = 26

9 (x - 2) = 27

What are the solutions to the equation (x+3)(x+2)=x+13 ?
The solutions to the equation (x+3)(x+2)=x+13 are x=-2+sqrt(11),x=-2-sqrt(11)
Find the zeros of (x+3)(x+2)=x+13
The zeros of (x+3)(x+2)=x+13 are x=-2+sqrt(11),x=-2-sqrt(11)