What are the solutions to the equation x^2-2x-63=0 ?

The solutions to the equation x^2-2x-63=0 are x=9,x=-7

Find the zeros of x^2-2x-63=0

The zeros of x^2-2x-63=0 are x=9,x=-7

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x^{2} - 2 x - 63 = 0

x = 9, x = - 7

Solution steps

x^{2} - 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- ( - 2 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 16}{2 \cdot 1}

x = \frac{- ( - 2 ) + 16}{2 \cdot 1} : 9

x = \frac{- ( - 2 ) - 16}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 9, x = - 7

y^{2} = 1

lo g_{3} (9) + lo g_{3} (27)

2^{2} + 1^{2} = c^{2}

x^{2} > 3

What are the solutions to the equation x^2-2x-63=0 ?
The solutions to the equation x^2-2x-63=0 are x=9,x=-7
Find the zeros of x^2-2x-63=0
The zeros of x^2-2x-63=0 are x=9,x=-7