What are the solutions to the equation -27=2x^2+3x ?

The solutions to the equation -27=2x^2+3x are x=-3/4+i(3sqrt(23))/4 ,x=-3/4-i(3sqrt(23))/4

Find the zeros of -27=2x^2+3x

The zeros of -27=2x^2+3x are x=-3/4+i(3sqrt(23))/4 ,x=-3/4-i(3sqrt(23))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 27 = 2 x^{2} + 3 x

x = - \frac{3}{4} + i \frac{3 23}{4}, x = - \frac{3}{4} - i \frac{3 23}{4}

Solution steps

- 27 = 2 x^{2} + 3 x

Switch sides

2 x^{2} + 3 x = - 27

Move

27

to the left side

2 x^{2} + 3 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 27}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 27 : 323 i

x_{1, 2} = \frac{- 3 \pm 3 23 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 3 23 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 3 23 i}{2 \cdot 2}

x = \frac{- 3 + 3 23 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{3 23}{4}

x = \frac{- 3 - 3 23 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{3 23}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{3 23}{4}, x = - \frac{3}{4} - i \frac{3 23}{4}

81 m^{4} - 1

\frac{- 112}{7 + 9}

2 x^{2} - 14 x^{2} + 24 x

5 t - 3 < - 33

2 x^{2} - x - 3 \geq 0

What are the solutions to the equation -27=2x^2+3x ?
The solutions to the equation -27=2x^2+3x are x=-3/4+i(3sqrt(23))/4 ,x=-3/4-i(3sqrt(23))/4
Find the zeros of -27=2x^2+3x
The zeros of -27=2x^2+3x are x=-3/4+i(3sqrt(23))/4 ,x=-3/4-i(3sqrt(23))/4