What are the solutions to the equation (X+3)^2=2X+6 ?

The solutions to the equation (X+3)^2=2X+6 are X=-1,X=-3

Find the zeros of (X+3)^2=2X+6

The zeros of (X+3)^2=2X+6 are X=-1,X=-3

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(X + 3)^{2} = 2 X + 6

X = - 1, X = - 3

Solution steps

(X + 3)^{2} = 2 X + 6

Expand

(X + 3)^{2} : X^{2} + 6 X + 9

X^{2} + 6 X + 9 = 2 X + 6

Move

6

to the left side

X^{2} + 6 X + 3 = 2 X

Move

2 X

to the left side

X^{2} + 4 X + 3 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

X_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 4 + 2}{2 \cdot 1}, X_{2} = \frac{- 4 - 2}{2 \cdot 1}

X = \frac{- 4 + 2}{2 \cdot 1} : - 1

X = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

X = - 1, X = - 3

11 q + 5 \leq 49

\frac{5}{4} \cdot \frac{3}{10}

a^{2} b - b^{2} c + a^{2} c - b c^{2}

\frac{650 - 559}{20 - 18.2}

2 x - 3 < 7

What are the solutions to the equation (X+3)^2=2X+6 ?
The solutions to the equation (X+3)^2=2X+6 are X=-1,X=-3
Find the zeros of (X+3)^2=2X+6
The zeros of (X+3)^2=2X+6 are X=-1,X=-3