What are the solutions to the equation 3(x-2)^2=24 ?

The solutions to the equation 3(x-2)^2=24 are x=2sqrt(2)+2,x=-2sqrt(2)+2

Find the zeros of 3(x-2)^2=24

The zeros of 3(x-2)^2=24 are x=2sqrt(2)+2,x=-2sqrt(2)+2

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3 (x - 2)^{2} = 24

x = 22 + 2, x = - 22 + 2

Decimal Notation

x = 4.82842 \dots, x = - 0.82842 \dots

Solution steps

3 (x - 2)^{2} = 24

Divide both sides by

3

(x - 2)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 8 : x = 22 + 2

Solve

x - 2 = - 8 : x = - 22 + 2

The solutions to the quadratic equation are:

x = 22 + 2, x = - 22 + 2

- 9 (4 + x) > - 126

12 (x + 3) x^{2} - 2 (x + 3) x - 4 (x + 3)

2 x - \frac{1}{4} x = - 28

- 3 x^{2} + 6 x + 9

4 r^{2} = - 28 r

What are the solutions to the equation 3(x-2)^2=24 ?
The solutions to the equation 3(x-2)^2=24 are x=2sqrt(2)+2,x=-2sqrt(2)+2
Find the zeros of 3(x-2)^2=24
The zeros of 3(x-2)^2=24 are x=2sqrt(2)+2,x=-2sqrt(2)+2