What are the solutions to the equation 8x^2+22x=21 ?

The solutions to the equation 8x^2+22x=21 are x= 3/4 ,x=-7/2

Find the zeros of 8x^2+22x=21

The zeros of 8x^2+22x=21 are x= 3/4 ,x=-7/2

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8 x^{2} + 22 x = 21

x = \frac{3}{4}, x = - \frac{7}{2}

Decimal Notation

x = 0.75, x = - 3.5

Solution steps

8 x^{2} + 22 x = 21

Move

21

to the left side

8 x^{2} + 22 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 8 ( - 21 )}{2 \cdot 8}

2 2^{2} - 4 \cdot 8 (- 21) = 34

x_{1, 2} = \frac{- 22 \pm 34}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 22 + 34}{2 \cdot 8}, x_{2} = \frac{- 22 - 34}{2 \cdot 8}

x = \frac{- 22 + 34}{2 \cdot 8} : \frac{3}{4}

x = \frac{- 22 - 34}{2 \cdot 8} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{7}{2}

4 x^{2} - 2 x + 8 = 0

16 x^{4} + 56 x^{2} + 49

x^{2} + 11 x + 30

\frac{3 ( 100 ) ^{2} + 1}{( 100 - 8 ) ^{2}}

\frac{( 5 x - 1 )}{3} > 3

What are the solutions to the equation 8x^2+22x=21 ?
The solutions to the equation 8x^2+22x=21 are x= 3/4 ,x=-7/2
Find the zeros of 8x^2+22x=21
The zeros of 8x^2+22x=21 are x= 3/4 ,x=-7/2