What are the solutions to the equation 10g^2+10=29g ?

The solutions to the equation 10g^2+10=29g are g= 5/2 ,g= 2/5

Find the zeros of 10g^2+10=29g

The zeros of 10g^2+10=29g are g= 5/2 ,g= 2/5

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10 g^{2} + 10 = 29 g

g = \frac{5}{2}, g = \frac{2}{5}

Decimal Notation

g = 2.5, g = 0.4

Solution steps

10 g^{2} + 10 = 29 g

Move

29 g

to the left side

10 g^{2} + 10 - 29 g = 0

Write in the standard form

a x^{2} + b x + c = 0

10 g^{2} - 29 g + 10 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 29)^{2} - 4 \cdot 10 \cdot 10 = 21

g_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 10}

Separate the solutions

g_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 10}, g_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 10}

g = \frac{- ( - 29 ) + 21}{2 \cdot 10} : \frac{5}{2}

g = \frac{- ( - 29 ) - 21}{2 \cdot 10} : \frac{2}{5}

The solutions to the quadratic equation are:

g = \frac{5}{2}, g = \frac{2}{5}

2 - x^{2} = x^{2}

x (x + 1) = 1.5 x^{2}

- 5 x + 4 (2 x + 2) = - 1

3 (1 - 2 x) = \frac{1}{4} (6 x + 9)

- 4 ∣ 2 w + 6 ∣ = - 32

What are the solutions to the equation 10g^2+10=29g ?
The solutions to the equation 10g^2+10=29g are g= 5/2 ,g= 2/5
Find the zeros of 10g^2+10=29g
The zeros of 10g^2+10=29g are g= 5/2 ,g= 2/5