What is ((2x+3))/(x^2+2x-15)>= 0 ?

The solution to ((2x+3))/(x^2+2x-15)>= 0 is -5 3

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((2x+3))/(x^2+2x-15)>= 0

\frac{( 2 x + 3 )}{x ^{2} + 2 x - 15} \geq 0

- 5 < x \leq - \frac{3}{2} or x > 3

Interval Notation

(- 5, - \frac{3}{2}] \cup (3, \infty)

Decimal Notation

- 5 < x \leq - 1.5 or x > 3

Solution steps

\frac{2 x + 3}{x ^{2} + 2 x - 15} \geq 0

Factor

\frac{2 x + 3}{x ^{2} + 2 x - 15} : \frac{2 x + 3}{( x - 3 ) ( x + 5 )}

\frac{2 x + 3}{( x - 3 ) ( x + 5 )} \geq 0

Identify the intervals

- 5 < x \leq - \frac{3}{2} or x > 3

∣ 3 x - 2 ∣ = 8

∣ x + 1 ∣ < 4

\frac{3 ^{n + 1} - 1 + 2 \cdot 3 ^{n + 1}}{2}

2 (a - 8) + 7 = 5 (a + 2) - 3 a - 19

\frac{2 π}{3} \cdot 2

What is ((2x+3))/(x^2+2x-15)>= 0 ?
The solution to ((2x+3))/(x^2+2x-15)>= 0 is -5<x<=-3/2 \lor x>3