What are the solutions to the equation x^2=5x+2 ?

The solutions to the equation x^2=5x+2 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2

Find the zeros of x^2=5x+2

The zeros of x^2=5x+2 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2

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x^{2} = 5 x + 2

x = \frac{5 + 33}{2}, x = \frac{5 - 33}{2}

Decimal Notation

x = 5.37228 \dots, x = - 0.37228 \dots

Solution steps

x^{2} = 5 x + 2

Move

2

to the left side

x^{2} - 2 = 5 x

Move

5 x

to the left side

x^{2} - 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 2) = 33

x_{1, 2} = \frac{- ( - 5 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 33}{2 \cdot 1}

x = \frac{- ( - 5 ) + 33}{2 \cdot 1} : \frac{5 + 33}{2}

x = \frac{- ( - 5 ) - 33}{2 \cdot 1} : \frac{5 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 33}{2}, x = \frac{5 - 33}{2}

3 x - 9 = 24

(3 p^{7})^{4}

69

2 \cdot 1 0^{6}

r^{2} + 18 r + 82 = 0

What are the solutions to the equation x^2=5x+2 ?
The solutions to the equation x^2=5x+2 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2
Find the zeros of x^2=5x+2
The zeros of x^2=5x+2 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2