What are the solutions to the equation 2x^2+6x-6=0 ?

The solutions to the equation 2x^2+6x-6=0 are x=(-3+sqrt(21))/2 ,x=-(3+sqrt(21))/2

Find the zeros of 2x^2+6x-6=0

The zeros of 2x^2+6x-6=0 are x=(-3+sqrt(21))/2 ,x=-(3+sqrt(21))/2

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2 x^{2} + 6 x - 6 = 0

x = \frac{- 3 + 21}{2}, x = - \frac{3 + 21}{2}

Decimal Notation

x = 0.79128 \dots, x = - 3.79128 \dots

Solution steps

2 x^{2} + 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 6) = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 21}{2 \cdot 2}

x = \frac{- 6 + 2 21}{2 \cdot 2} : \frac{- 3 + 21}{2}

x = \frac{- 6 - 2 21}{2 \cdot 2} : - \frac{3 + 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 21}{2}, x = - \frac{3 + 21}{2}

2 7^{- \frac{1}{3}}

2 a^{2} x + 2 a x^{2} - 3 a x

(- 64)^{\frac{3}{2}}

- 12

8 (z + 7) - 5 = 67

What are the solutions to the equation 2x^2+6x-6=0 ?
The solutions to the equation 2x^2+6x-6=0 are x=(-3+sqrt(21))/2 ,x=-(3+sqrt(21))/2
Find the zeros of 2x^2+6x-6=0
The zeros of 2x^2+6x-6=0 are x=(-3+sqrt(21))/2 ,x=-(3+sqrt(21))/2