What are the solutions to the equation n^2=9n-20 ?

The solutions to the equation n^2=9n-20 are n=5,n=4

Find the zeros of n^2=9n-20

The zeros of n^2=9n-20 are n=5,n=4

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n^{2} = 9 n - 20

n = 5, n = 4

Solution steps

n^{2} = 9 n - 20

Move

20

to the left side

n^{2} + 20 = 9 n

Move

9 n

to the left side

n^{2} + 20 - 9 n = 0

Write in the standard form

a x^{2} + b x + c = 0

n^{2} - 9 n + 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

n_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, n_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

n = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

n = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

n = 5, n = 4

20 x + 12 \geq 14 x + 30

\frac{1}{2} (- 2)^{- 4} 4^{2}

8 - ∣ 2 x - 1 ∣ \geq 6

\frac{π}{2} - π

\frac{2}{5} - \frac{1}{6}

What are the solutions to the equation n^2=9n-20 ?
The solutions to the equation n^2=9n-20 are n=5,n=4
Find the zeros of n^2=9n-20
The zeros of n^2=9n-20 are n=5,n=4