What are the solutions to the equation x^2+14x-16=0 ?

The solutions to the equation x^2+14x-16=0 are x=-7+sqrt(65),x=-7-sqrt(65)

Find the zeros of x^2+14x-16=0

The zeros of x^2+14x-16=0 are x=-7+sqrt(65),x=-7-sqrt(65)

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x^{2} + 14 x - 16 = 0

x = - 7 + 65, x = - 7 - 65

Decimal Notation

x = 1.06225 \dots, x = - 15.06225 \dots

Solution steps

x^{2} + 14 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 16) = 265

x_{1, 2} = \frac{- 14 \pm 2 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 65}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 65}{2 \cdot 1}

x = \frac{- 14 + 2 65}{2 \cdot 1} : - 7 + 65

x = \frac{- 14 - 2 65}{2 \cdot 1} : - 7 - 65

The solutions to the quadratic equation are:

x = - 7 + 65, x = - 7 - 65

5 t^{2} - 14 t + 6 = 0

(x - 4) (x + 5) < 0

6 t^{2} - 18 t

(2 + 2 i)^{2}

\frac{x}{8} - \frac{x}{9} = 1

What are the solutions to the equation x^2+14x-16=0 ?
The solutions to the equation x^2+14x-16=0 are x=-7+sqrt(65),x=-7-sqrt(65)
Find the zeros of x^2+14x-16=0
The zeros of x^2+14x-16=0 are x=-7+sqrt(65),x=-7-sqrt(65)