What are the solutions to the equation n^2+10n+7=0 ?

The solutions to the equation n^2+10n+7=0 are n=-5+3sqrt(2),n=-5-3sqrt(2)

Find the zeros of n^2+10n+7=0

The zeros of n^2+10n+7=0 are n=-5+3sqrt(2),n=-5-3sqrt(2)

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n^{2} + 10 n + 7 = 0

n = - 5 + 32, n = - 5 - 32

Decimal Notation

n = - 0.75735 \dots, n = - 9.24264 \dots

Solution steps

n^{2} + 10 n + 7 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 7 = 62

n_{1, 2} = \frac{- 10 \pm 6 2}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 10 + 6 2}{2 \cdot 1}, n_{2} = \frac{- 10 - 6 2}{2 \cdot 1}

n = \frac{- 10 + 6 2}{2 \cdot 1} : - 5 + 32

n = \frac{- 10 - 6 2}{2 \cdot 1} : - 5 - 32

The solutions to the quadratic equation are:

n = - 5 + 32, n = - 5 - 32

1 - m^{6}

\frac{5 x - 105}{7 ( x + 3 )}

(24 x^{4} - 15 x^{2} + 6 x) - (10 x^{4} + 5 x^{2} - 4 x)

3 (3) + 10 (5) \leq 8

\frac{1}{16} - 9 z^{2}

What are the solutions to the equation n^2+10n+7=0 ?
The solutions to the equation n^2+10n+7=0 are n=-5+3sqrt(2),n=-5-3sqrt(2)
Find the zeros of n^2+10n+7=0
The zeros of n^2+10n+7=0 are n=-5+3sqrt(2),n=-5-3sqrt(2)