What is the answer to (2x)/3+(4x-1)/5 =2 ?

The answer to (2x)/3+(4x-1)/5 =2 is x= 3/2

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(2x)/3+(4x-1)/5 =2

\frac{2 x}{3} + \frac{4 x - 1}{5} = 2

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

\frac{2 x}{3} + \frac{4 x - 1}{5} = 2

Multiply by LCM

10 x + 3 (4 x - 1) = 30

Expand

3 (4 x - 1) : 12 x - 3

10 x + 12 x - 3 = 30

Add similar elements:

10 x + 12 x = 22 x

22 x - 3 = 30

Move

3

to the right side

22 x = 33

Divide both sides by

22

x = \frac{3}{2}

\frac{7.6 1 ^{2}}{14}

\frac{14 !}{( 14 - 6 ) ! 6 !}

(1 + \frac{2}{n})^{n}

x^{2} - 7 = 6 x

What is the answer to (2x)/3+(4x-1)/5 =2 ?
The answer to (2x)/3+(4x-1)/5 =2 is x= 3/2
Solve for x: (2x)/3+(4x-1)/5 =2
The solution is x= 3/2