What are the solutions to the equation (x+2)(x-3)=0 ?

The solutions to the equation (x+2)(x-3)=0 are x=-2,x=3

Find the zeros of (x+2)(x-3)=0

The zeros of (x+2)(x-3)=0 are x=-2,x=3

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(x + 2) (x - 3) = 0

x = - 2, x = 3

Solution steps

(x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 2, x = 3

10 (1 + 3 b) = - 20

m^{2} - 3 m = 0

x^{2} - 6 x + 13

- 10 < 4 z - 6 \leq 22

\frac{6 !}{3 !}

What are the solutions to the equation (x+2)(x-3)=0 ?
The solutions to the equation (x+2)(x-3)=0 are x=-2,x=3
Find the zeros of (x+2)(x-3)=0
The zeros of (x+2)(x-3)=0 are x=-2,x=3