What are the solutions to the equation 4^2+b^2=5^2 ?

The solutions to the equation 4^2+b^2=5^2 are b=3,b=-3

Find the zeros of 4^2+b^2=5^2

The zeros of 4^2+b^2=5^2 are b=3,b=-3

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4^{2} + b^{2} = 5^{2}

b = 3, b = - 3

Solution steps

4^{2} + b^{2} = 5^{2}

Move

4^{2}

to the right side

b^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 9, b = - 9

9 = 3

- 9 = - 3

b = 3, b = - 3

\frac{2 x y}{x ^{2} - y ^{2}}

- 5 \leq - 10 x < 5

∣ 2 x + 4 ∣ \geq 5

16 x^{2} - 64 = 0

What are the solutions to the equation 4^2+b^2=5^2 ?
The solutions to the equation 4^2+b^2=5^2 are b=3,b=-3
Find the zeros of 4^2+b^2=5^2
The zeros of 4^2+b^2=5^2 are b=3,b=-3