What are the solutions to the equation 4x^2+10x=-3 ?

The solutions to the equation 4x^2+10x=-3 are x=(-5+sqrt(13))/4 ,x=-(5+sqrt(13))/4

Find the zeros of 4x^2+10x=-3

The zeros of 4x^2+10x=-3 are x=(-5+sqrt(13))/4 ,x=-(5+sqrt(13))/4

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4 x^{2} + 10 x = - 3

x = \frac{- 5 + 13}{4}, x = - \frac{5 + 13}{4}

Decimal Notation

x = - 0.34861 \dots, x = - 2.15138 \dots

Solution steps

4 x^{2} + 10 x = - 3

Move

3

to the left side

4 x^{2} + 10 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

1 0^{2} - 4 \cdot 4 \cdot 3 = 213

x_{1, 2} = \frac{- 10 \pm 2 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 10 + 2 13}{2 \cdot 4}, x_{2} = \frac{- 10 - 2 13}{2 \cdot 4}

x = \frac{- 10 + 2 13}{2 \cdot 4} : \frac{- 5 + 13}{4}

x = \frac{- 10 - 2 13}{2 \cdot 4} : - \frac{5 + 13}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{4}, x = - \frac{5 + 13}{4}

2.61704 \cdot (\frac{1}{2})^{\frac{1000}{24100}}

- 0.5244 = \frac{x - 54}{16}

3 + a < 2

35 x + 10 = 150

x - 2 \leq 4 x + 7

What are the solutions to the equation 4x^2+10x=-3 ?
The solutions to the equation 4x^2+10x=-3 are x=(-5+sqrt(13))/4 ,x=-(5+sqrt(13))/4
Find the zeros of 4x^2+10x=-3
The zeros of 4x^2+10x=-3 are x=(-5+sqrt(13))/4 ,x=-(5+sqrt(13))/4