What are the solutions to the equation 4/9 p^2-25=0 ?

The solutions to the equation 4/9 p^2-25=0 are p= 15/2 ,p=-15/2

Find the zeros of 4/9 p^2-25=0

The zeros of 4/9 p^2-25=0 are p= 15/2 ,p=-15/2

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\frac{4}{9} p^{2} - 25 = 0

p = \frac{15}{2}, p = - \frac{15}{2}

Decimal Notation

p = 7.5, p = - 7.5

Solution steps

\frac{4}{9} p^{2} - 25 = 0

Move

25

to the right side

\frac{4}{9} p^{2} = 25

Multiply both sides by

9

4 p^{2} = 225

Divide both sides by

4

p^{2} = \frac{225}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = \frac{225}{4}, p = - \frac{225}{4}

\frac{225}{4} = \frac{15}{2}

- \frac{225}{4} = - \frac{15}{2}

p = \frac{15}{2}, p = - \frac{15}{2}

- 5 \geq \frac{b}{- 8}

e^{- l n (7)}

0^{\circ} < θ < 36 0^{\circ}

x^{4} - 10 x^{2} + 9 = 0

a (\frac{b ( e ^{b t} - 1 )}{t} - b e^{b t} \frac{1}{t} + e^{b t} \frac{1}{t ^{2}} - \frac{1}{t ^{2}})

What are the solutions to the equation 4/9 p^2-25=0 ?
The solutions to the equation 4/9 p^2-25=0 are p= 15/2 ,p=-15/2
Find the zeros of 4/9 p^2-25=0
The zeros of 4/9 p^2-25=0 are p= 15/2 ,p=-15/2