What are the solutions to the equation 3x^2-4x+15=0 ?

The solutions to the equation 3x^2-4x+15=0 are x= 2/3+i(sqrt(41))/3 ,x= 2/3-i(sqrt(41))/3

Find the zeros of 3x^2-4x+15=0

The zeros of 3x^2-4x+15=0 are x= 2/3+i(sqrt(41))/3 ,x= 2/3-i(sqrt(41))/3

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3 x^{2} - 4 x + 15 = 0

x = \frac{2}{3} + i \frac{41}{3}, x = \frac{2}{3} - i \frac{41}{3}

Solution steps

3 x^{2} - 4 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 15 : 241 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 41 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 41 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 41 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 41 i}{2 \cdot 3} : \frac{2}{3} + i \frac{41}{3}

x = \frac{- ( - 4 ) - 2 41 i}{2 \cdot 3} : \frac{2}{3} - i \frac{41}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{41}{3}, x = \frac{2}{3} - i \frac{41}{3}

\frac{y - 1}{2} - \frac{2 y + 3}{8} - y > 2

49 s^{2} - 144

(16 x^{\frac{1}{4}} y^{\frac{3}{4}})^{- 4}

6 y^{2} + 13 y + 6

2 (2 x + 7) = 42

What are the solutions to the equation 3x^2-4x+15=0 ?
The solutions to the equation 3x^2-4x+15=0 are x= 2/3+i(sqrt(41))/3 ,x= 2/3-i(sqrt(41))/3
Find the zeros of 3x^2-4x+15=0
The zeros of 3x^2-4x+15=0 are x= 2/3+i(sqrt(41))/3 ,x= 2/3-i(sqrt(41))/3