What are the solutions to the equation x^2+10x=6 ?

The solutions to the equation x^2+10x=6 are x=-5+sqrt(31),x=-5-sqrt(31)

Find the zeros of x^2+10x=6

The zeros of x^2+10x=6 are x=-5+sqrt(31),x=-5-sqrt(31)

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x^{2} + 10 x = 6

x = - 5 + 31, x = - 5 - 31

Decimal Notation

x = 0.56776 \dots, x = - 10.56776 \dots

Solution steps

x^{2} + 10 x = 6

Move

6

to the left side

x^{2} + 10 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 6) = 231

x_{1, 2} = \frac{- 10 \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 31}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 31}{2 \cdot 1}

x = \frac{- 10 + 2 31}{2 \cdot 1} : - 5 + 31

x = \frac{- 10 - 2 31}{2 \cdot 1} : - 5 - 31

The solutions to the quadratic equation are:

x = - 5 + 31, x = - 5 - 31

(x) (x + 1) = 2970

0 = - 16 t^{2} + 16 t + 32

[\frac{( x + 3 )}{( x + 8 )}] \geq 6

19 - 3 x \leq - (1 + 7 x)

- (a + 1) - 4 a \leq 2 a - 8

What are the solutions to the equation x^2+10x=6 ?
The solutions to the equation x^2+10x=6 are x=-5+sqrt(31),x=-5-sqrt(31)
Find the zeros of x^2+10x=6
The zeros of x^2+10x=6 are x=-5+sqrt(31),x=-5-sqrt(31)