What are the solutions to the equation 0=1.5x^2-4.5x ?

The solutions to the equation 0=1.5x^2-4.5x are x=3,x=0

Find the zeros of 0=1.5x^2-4.5x

The zeros of 0=1.5x^2-4.5x are x=3,x=0

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0 = 1.5 x^{2} - 4.5 x

x = 3, x = 0

Solution steps

0 = 1.5 x^{2} - 4.5 x

Multiply both sides by

10

0 = 15 x^{2} - 45 x

Switch sides

15 x^{2} - 45 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 45 ) \pm ( - 45 ) ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

(- 45)^{2} - 4 \cdot 15 \cdot 0 = 45

x_{1, 2} = \frac{- ( - 45 ) \pm 45}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 45 ) + 45}{2 \cdot 15}, x_{2} = \frac{- ( - 45 ) - 45}{2 \cdot 15}

x = \frac{- ( - 45 ) + 45}{2 \cdot 15} : 3

x = \frac{- ( - 45 ) - 45}{2 \cdot 15} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

\frac{16}{25} x^{2} y^{2} - \frac{36}{49} y^{4}

3 x = 42

\frac{x}{15} + 3 = 4

1 - \frac{9}{16}

8 1^{\frac{3}{2}}

What are the solutions to the equation 0=1.5x^2-4.5x ?
The solutions to the equation 0=1.5x^2-4.5x are x=3,x=0
Find the zeros of 0=1.5x^2-4.5x
The zeros of 0=1.5x^2-4.5x are x=3,x=0