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Popular >

simplify (z+i)(z-i)

Solution

simplify

(z + i) (z - i)

Solution

z^{2} + 1

Solution steps

(z + i) (z - i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= z^{2} + 1^{2}

1^{2} = 1

= z^{2} + 1

Popular Examples

factor 3x^2-13x+12 factor

3 x^{2} - 13 x + 12

4 x^{2} + 5 x + 11 = 0

factor 1/(x-1)-(3x+3)/(x^2+x-2)+1/(x+2)factor

\frac{1}{x - 1} - \frac{3 x + 3}{x ^{2} + x - 2} + \frac{1}{x + 2}

11+3(-8+5x)<16x-5

11 + 3 (- 8 + 5 x) < 16 x - 5

- 2 (1 - 4 x) = 3 x + 8

Frequently Asked Questions (FAQ)

What is (z+i)(z-i) ?
The solution to (z+i)(z-i) is z^2+1