What is (4b+10c)(10c-4b)+(-5c+2b)(5c+2b) ?

The solution to (4b+10c)(10c-4b)+(-5c+2b)(5c+2b) is 75c^2-12b^2

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simplify (4b+10c)(10c-4b)+(-5c+2b)(5c+2b)

simplify

(4 b + 10 c) (10 c - 4 b) + (- 5 c + 2 b) (5 c + 2 b)

75 c^{2} - 12 b^{2}

Solution steps

(4 b + 10 c) (10 c - 4 b) + (- 5 c + 2 b) (5 c + 2 b)

Expand

(4 b + 10 c) (10 c - 4 b) : 100 c^{2} - 16 b^{2}

= 100 c^{2} - 16 b^{2} + (- 5 c + 2 b) (5 c + 2 b)

Expand

(- 5 c + 2 b) (5 c + 2 b) : 4 b^{2} - 25 c^{2}

= 100 c^{2} - 16 b^{2} + 4 b^{2} - 25 c^{2}

Add similar elements:

- 16 b^{2} + 4 b^{2} = - 12 b^{2}

= 100 c^{2} - 12 b^{2} - 25 c^{2}

Group like terms

= 100 c^{2} - 25 c^{2} - 12 b^{2}

Add similar elements:

100 c^{2} - 25 c^{2} = 75 c^{2}

= 75 c^{2} - 12 b^{2}

227

4 (\frac{3}{2})^{- 1}

a + b - c - b - c + 2 c - a

f (lo g_{10} (4 - x^{2}))

\frac{3}{10} \geq k - \frac{3}{5}

What is (4b+10c)(10c-4b)+(-5c+2b)(5c+2b) ?
The solution to (4b+10c)(10c-4b)+(-5c+2b)(5c+2b) is 75c^2-12b^2