What are the solutions to the equation x^2+11x-26=0 ?

The solutions to the equation x^2+11x-26=0 are x=2,x=-13

Find the zeros of x^2+11x-26=0

The zeros of x^2+11x-26=0 are x=2,x=-13

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x^{2} + 11 x - 26 = 0

x = 2, x = - 13

Solution steps

x^{2} + 11 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 26) = 15

x_{1, 2} = \frac{- 11 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 15}{2 \cdot 1}, x_{2} = \frac{- 11 - 15}{2 \cdot 1}

x = \frac{- 11 + 15}{2 \cdot 1} : 2

x = \frac{- 11 - 15}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 2, x = - 13

2 ∣ x + 1 ∣ + 3 = 9

5 x \leq 21 + 2 x or 3 (x + 1) \geq 24

\frac{5}{6} = \frac{w + 3}{7}

\frac{x}{4} = 4 - \frac{x + 2}{3}

\frac{1}{2} \cdot 6 \cdot 7

What are the solutions to the equation x^2+11x-26=0 ?
The solutions to the equation x^2+11x-26=0 are x=2,x=-13
Find the zeros of x^2+11x-26=0
The zeros of x^2+11x-26=0 are x=2,x=-13