What are the solutions to the equation 3x^2-114=-x ?

The solutions to the equation 3x^2-114=-x are x=6,x=-19/3

Find the zeros of 3x^2-114=-x

The zeros of 3x^2-114=-x are x=6,x=-19/3

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3 x^{2} - 114 = - x

x = 6, x = - \frac{19}{3}

Decimal Notation

x = 6, x = - 6.33333 \dots

Solution steps

3 x^{2} - 114 = - x

Move

x

to the left side

3 x^{2} - 114 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + x - 114 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 114 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 114) = 37

x_{1, 2} = \frac{- 1 \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 37}{2 \cdot 3}, x_{2} = \frac{- 1 - 37}{2 \cdot 3}

x = \frac{- 1 + 37}{2 \cdot 3} : 6

x = \frac{- 1 - 37}{2 \cdot 3} : - \frac{19}{3}

The solutions to the quadratic equation are:

x = 6, x = - \frac{19}{3}

x = 1^{2}

5 x^{2} + 9 x y + 4 y^{2}

\frac{1}{2} \cdot 4 \cdot 5

x^{2} + 14 x y + 48 y^{2}

\frac{\frac{1}{4}}{4}

What are the solutions to the equation 3x^2-114=-x ?
The solutions to the equation 3x^2-114=-x are x=6,x=-19/3
Find the zeros of 3x^2-114=-x
The zeros of 3x^2-114=-x are x=6,x=-19/3