What are the solutions to the equation 15x^2+16x+4=0 ?

The solutions to the equation 15x^2+16x+4=0 are x=-2/5 ,x=-2/3

Find the zeros of 15x^2+16x+4=0

The zeros of 15x^2+16x+4=0 are x=-2/5 ,x=-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

15 x^{2} + 16 x + 4 = 0

x = - \frac{2}{5}, x = - \frac{2}{3}

Decimal Notation

x = - 0.4, x = - 0.66666 \dots

Solution steps

15 x^{2} + 16 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 15 \cdot 4}{2 \cdot 15}

1 6^{2} - 4 \cdot 15 \cdot 4 = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 \cdot 15}, x_{2} = \frac{- 16 - 4}{2 \cdot 15}

x = \frac{- 16 + 4}{2 \cdot 15} : - \frac{2}{5}

x = \frac{- 16 - 4}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - \frac{2}{3}

6^{2} + 3^{2}

\frac{( \frac{x}{y} )}{x}

- \frac{5}{2} + 1

(1 + \frac{0.09}{365})^{365} - 1

20 n^{2} - 65 n - 175 = 0

What are the solutions to the equation 15x^2+16x+4=0 ?
The solutions to the equation 15x^2+16x+4=0 are x=-2/5 ,x=-2/3
Find the zeros of 15x^2+16x+4=0
The zeros of 15x^2+16x+4=0 are x=-2/5 ,x=-2/3