What are the solutions to the equation 9x^2-12x+4=0 ?

The solutions to the equation 9x^2-12x+4=0 are x= 2/3

Find the zeros of 9x^2-12x+4=0

The zeros of 9x^2-12x+4=0 are x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 12 x + 4 = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

9 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

(\frac{x ^{2}}{x - 5}) \geq 0

1 \cdot \frac{1}{2}

a^{2} - 12 a + 32

1 < ∣ x ∣ < 5

5 \cdot 2

What are the solutions to the equation 9x^2-12x+4=0 ?
The solutions to the equation 9x^2-12x+4=0 are x= 2/3
Find the zeros of 9x^2-12x+4=0
The zeros of 9x^2-12x+4=0 are x= 2/3