What is (-5b^3)/6*(3b^2)/(-10) ?

The solution to (-5b^3)/6*(3b^2)/(-10) is (b^5)/4

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simplify (-5b^3)/6*(3b^2)/(-10)

simplify

\frac{- 5 b ^{3}}{6} \cdot \frac{3 b ^{2}}{- 10}

\frac{b ^{5}}{4}

Solution steps

\frac{- 5 b ^{3}}{6} \cdot \frac{3 b ^{2}}{- 10}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 5 b ^{3}}{6} = - \frac{5 b ^{3}}{6}

= - \frac{5 b ^{3}}{6} \cdot \frac{3 b ^{2}}{- 10}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

\frac{3 b ^{2}}{- 10} = - \frac{3 b ^{2}}{10}

= - \frac{5 b ^{3}}{6} (- \frac{3 b ^{2}}{10})

Apply rule:

- a (- b) = ab

- \frac{5 b ^{3}}{6} (- \frac{3 b ^{2}}{10}) = \frac{5 b ^{3}}{6} \cdot \frac{3 b ^{2}}{10}

= \frac{5 b ^{3}}{6} \cdot \frac{3 b ^{2}}{10}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 b ^{3} \cdot 3 b ^{2}}{6 \cdot 10}

Cancel

\frac{5 b ^{3} \cdot 3 b ^{2}}{6 \cdot 10} : \frac{b ^{3} b ^{2}}{2 \cdot 2}

= \frac{b ^{3} b ^{2}}{2 \cdot 2}

Simplify

b^{3} b^{2} : b^{5}

= \frac{b ^{5}}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{b ^{5}}{4}

\frac{π}{3} \cdot 3

(11 - 3)^{2} + (11 + 3)^{2}

∣ x - 4 ∣ > - 1

\frac{3 x - 2}{x - 1} \geq 0

(31/2) + 96 + 5 + 9 + (26/2) + 17

What is (-5b^3)/6*(3b^2)/(-10) ?
The solution to (-5b^3)/6*(3b^2)/(-10) is (b^5)/4