What are the solutions to the equation 4m^2-4m+1=0 ?

The solutions to the equation 4m^2-4m+1=0 are m= 1/2

Find the zeros of 4m^2-4m+1=0

The zeros of 4m^2-4m+1=0 are m= 1/2

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4 m^{2} - 4 m + 1 = 0

m = \frac{1}{2}

Decimal Notation

m = 0.5

Solution steps

4 m^{2} - 4 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

m_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

m = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

m = \frac{1}{2}

The solution to the quadratic equation is:

m = \frac{1}{2}

6 x^{2} + 2 x = 4

9 x - 10 - x = 1 + 3 (3 x - 3)

- \frac{3}{2} - \frac{5}{3}

\frac{2}{8 i}

6 + 3 ∣ 3 x + 7 ∣ = 24

What are the solutions to the equation 4m^2-4m+1=0 ?
The solutions to the equation 4m^2-4m+1=0 are m= 1/2
Find the zeros of 4m^2-4m+1=0
The zeros of 4m^2-4m+1=0 are m= 1/2