What are the solutions to the equation 25x^2+16=40x ?

The solutions to the equation 25x^2+16=40x are x= 4/5

Find the zeros of 25x^2+16=40x

The zeros of 25x^2+16=40x are x= 4/5

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25 x^{2} + 16 = 40 x

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

25 x^{2} + 16 = 40 x

Move

40 x

to the left side

25 x^{2} + 16 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 40 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

x = \frac{4}{5}

The solution to the quadratic equation is:

x = \frac{4}{5}

3 x^{2} - 7 x = 6

\frac{3}{a ^{- 9} b}

(\frac{7}{8})^{- 2}

18 x^{2} - 3 x < 1

\frac{π}{\frac{1}{2}}

What are the solutions to the equation 25x^2+16=40x ?
The solutions to the equation 25x^2+16=40x are x= 4/5
Find the zeros of 25x^2+16=40x
The zeros of 25x^2+16=40x are x= 4/5