What are the solutions to the equation p^2+16p-22=0 ?

The solutions to the equation p^2+16p-22=0 are p=-8+sqrt(86),p=-8-sqrt(86)

Find the zeros of p^2+16p-22=0

The zeros of p^2+16p-22=0 are p=-8+sqrt(86),p=-8-sqrt(86)

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p^{2} + 16 p - 22 = 0

p = - 8 + 86, p = - 8 - 86

Decimal Notation

p = 1.27361 \dots, p = - 17.27361 \dots

Solution steps

p^{2} + 16 p - 22 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 22) = 286

p_{1, 2} = \frac{- 16 \pm 2 86}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 16 + 2 86}{2 \cdot 1}, p_{2} = \frac{- 16 - 2 86}{2 \cdot 1}

p = \frac{- 16 + 2 86}{2 \cdot 1} : - 8 + 86

p = \frac{- 16 - 2 86}{2 \cdot 1} : - 8 - 86

The solutions to the quadratic equation are:

p = - 8 + 86, p = - 8 - 86

- 3 x + 18 < 9

∣ 2 x ∣ \geq 6

y^{2} - 81 = 0

x^{4} + 3 x^{2} - 28

∣ 3 x + 5 ∣ = 1

What are the solutions to the equation p^2+16p-22=0 ?
The solutions to the equation p^2+16p-22=0 are p=-8+sqrt(86),p=-8-sqrt(86)
Find the zeros of p^2+16p-22=0
The zeros of p^2+16p-22=0 are p=-8+sqrt(86),p=-8-sqrt(86)