What are the solutions to the equation -12y^2-36y=0 ?

The solutions to the equation -12y^2-36y=0 are y=-3,y=0

Find the zeros of -12y^2-36y=0

The zeros of -12y^2-36y=0 are y=-3,y=0

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- 12 y^{2} - 36 y = 0

y = - 3, y = 0

Solution steps

- 12 y^{2} - 36 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

(- 36)^{2} - 4 (- 12) \cdot 0 = 36

y_{1, 2} = \frac{- ( - 36 ) \pm 36}{2 ( - 12 )}

Separate the solutions

y_{1} = \frac{- ( - 36 ) + 36}{2 ( - 12 )}, y_{2} = \frac{- ( - 36 ) - 36}{2 ( - 12 )}

y = \frac{- ( - 36 ) + 36}{2 ( - 12 )} : - 3

y = \frac{- ( - 36 ) - 36}{2 ( - 12 )} : 0

The solutions to the quadratic equation are:

y = - 3, y = 0

x^{2} - 18 = 0

(- \frac{2}{5})^{5}

∣ 7 x + 2 ∣ \leq 4

5 x + 7 < 6 x + 15 \leq 3 x + 21

x^{2} + x = 2 \cdot 60 \cdot \frac{5}{1}

What are the solutions to the equation -12y^2-36y=0 ?
The solutions to the equation -12y^2-36y=0 are y=-3,y=0
Find the zeros of -12y^2-36y=0
The zeros of -12y^2-36y=0 are y=-3,y=0