What are the solutions to the equation 0=16t^2+324 ?

The solutions to the equation 0=16t^2+324 are t= 9/2 i,t=-9/2 i

Find the zeros of 0=16t^2+324

The zeros of 0=16t^2+324 are t= 9/2 i,t=-9/2 i

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0 = 16 t^{2} + 324

t = \frac{9}{2} i, t = - \frac{9}{2} i

Solution steps

0 = 16 t^{2} + 324

Switch sides

16 t^{2} + 324 = 0

Move

324

to the right side

16 t^{2} = - 324

Divide both sides by

16

t^{2} = - \frac{81}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - \frac{81}{4}, t = - - \frac{81}{4}

- \frac{81}{4} = \frac{9}{2} i

- - \frac{81}{4} = - \frac{9}{2} i

t = \frac{9}{2} i, t = - \frac{9}{2} i

x^{2} - 2 x + 2 \geq 0

8.2 (x + 7) 7 = 24.6

2 x > 0

102 4^{\frac{4}{5}}

(\frac{4}{5})^{0}

What are the solutions to the equation 0=16t^2+324 ?
The solutions to the equation 0=16t^2+324 are t= 9/2 i,t=-9/2 i
Find the zeros of 0=16t^2+324
The zeros of 0=16t^2+324 are t= 9/2 i,t=-9/2 i