What are the solutions to the equation 4x^2-8x+3=0 ?

The solutions to the equation 4x^2-8x+3=0 are x= 3/2 ,x= 1/2

Find the zeros of 4x^2-8x+3=0

The zeros of 4x^2-8x+3=0 are x= 3/2 ,x= 1/2

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4 x^{2} - 8 x + 3 = 0

x = \frac{3}{2}, x = \frac{1}{2}

Decimal Notation

x = 1.5, x = 0.5

Solution steps

4 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 3 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 8 ) - 4}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{2}

\frac{x}{x - 6} \geq - 1

\frac{1}{5} + \frac{2}{7} - \frac{6}{11}

∣ x + 1 ∣ \geq 4

∣ 5 x - 4 ∣ < 1

- 4 n + 11 > - 9

What are the solutions to the equation 4x^2-8x+3=0 ?
The solutions to the equation 4x^2-8x+3=0 are x= 3/2 ,x= 1/2
Find the zeros of 4x^2-8x+3=0
The zeros of 4x^2-8x+3=0 are x= 3/2 ,x= 1/2