What is ((8^{-5})/(2^{-2)})^{-4} ?

The solution to ((8^{-5})/(2^{-2)})^{-4} is 2^{52}

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simplify ((8^{-5})/(2^{-2)})^{-4}

simplify

(\frac{8 ^{- 5}}{2 ^{- 2}})^{- 4}

2^{52}

Decimal Notation

4.5036 E 15

Solution steps

(\frac{8 ^{- 5}}{2 ^{- 2}})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{8 ^{- 5}}{2 ^{- 2}})^{- 4} = \frac{1}{( \frac{8 ^{- 5}}{2 ^{- 2}} ) ^{4}}

= \frac{1}{( \frac{8 ^{- 5}}{2 ^{- 2}} ) ^{4}}

(\frac{8 ^{- 5}}{2 ^{- 2}})^{4} = \frac{1}{2 ^{52}}

= \frac{1}{\frac{1}{2 ^{52}}}

\frac{1}{\frac{1}{2 ^{52}}} = 2^{52}

= 2^{52}

5 x^{2} (2 x^{2} + 1)^{4} (6 x) + (2 x^{2} + 1)^{5} (2 x)

- 3 x - 5 = 5 x - 61

36 w^{2} - 121

4 x^{2} - 8 x - 60

1^{2} + b^{2} = 5^{2}

What is ((8^{-5})/(2^{-2)})^{-4} ?
The solution to ((8^{-5})/(2^{-2)})^{-4} is 2^{52}