What are the solutions to the equation 8n^2+6n=-5 ?

The solutions to the equation 8n^2+6n=-5 are n=-3/8+i(sqrt(31))/8 ,n=-3/8-i(sqrt(31))/8

Find the zeros of 8n^2+6n=-5

The zeros of 8n^2+6n=-5 are n=-3/8+i(sqrt(31))/8 ,n=-3/8-i(sqrt(31))/8

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8 n^{2} + 6 n = - 5

n = - \frac{3}{8} + i \frac{31}{8}, n = - \frac{3}{8} - i \frac{31}{8}

Solution steps

8 n^{2} + 6 n = - 5

Move

5

to the left side

8 n^{2} + 6 n + 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

Simplify

6^{2} - 4 \cdot 8 \cdot 5 : 231 i

n_{1, 2} = \frac{- 6 \pm 2 31 i}{2 \cdot 8}

Separate the solutions

n_{1} = \frac{- 6 + 2 31 i}{2 \cdot 8}, n_{2} = \frac{- 6 - 2 31 i}{2 \cdot 8}

n = \frac{- 6 + 2 31 i}{2 \cdot 8} : - \frac{3}{8} + i \frac{31}{8}

n = \frac{- 6 - 2 31 i}{2 \cdot 8} : - \frac{3}{8} - i \frac{31}{8}

The solutions to the quadratic equation are:

n = - \frac{3}{8} + i \frac{31}{8}, n = - \frac{3}{8} - i \frac{31}{8}

x - 4 (- x + 5) = 10

2 x = 50

9 x + 2 = 6

2 - 1

5 x + 1 \leq 11

What are the solutions to the equation 8n^2+6n=-5 ?
The solutions to the equation 8n^2+6n=-5 are n=-3/8+i(sqrt(31))/8 ,n=-3/8-i(sqrt(31))/8
Find the zeros of 8n^2+6n=-5
The zeros of 8n^2+6n=-5 are n=-3/8+i(sqrt(31))/8 ,n=-3/8-i(sqrt(31))/8