What are the solutions to the equation (x-4)^2=1 ?

The solutions to the equation (x-4)^2=1 are x=5,x=3

Find the zeros of (x-4)^2=1

The zeros of (x-4)^2=1 are x=5,x=3

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(x - 4)^{2} = 1

x = 5, x = 3

Solution steps

(x - 4)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 1 : x = 5

Solve

x - 4 = - 1 : x = 3

The solutions to the quadratic equation are:

x = 5, x = 3

- 9 - 6

\frac{∣ x + 1 ∣}{∣ x - 2 ∣} < 1

x^{2} + x - 20 \geq 0

\frac{1 - 0.99}{0.99} \cdot 100

\frac{x ^{2} - x y}{9 y ^{2}} \cdot \frac{3 y}{2 x}

What are the solutions to the equation (x-4)^2=1 ?
The solutions to the equation (x-4)^2=1 are x=5,x=3
Find the zeros of (x-4)^2=1
The zeros of (x-4)^2=1 are x=5,x=3