What are the solutions to the equation 4x^2=12 ?

The solutions to the equation 4x^2=12 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 4x^2=12

The zeros of 4x^2=12 are x=sqrt(3),x=-sqrt(3)

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4 x^{2} = 12

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

4 x^{2} = 12

Divide both sides by

4

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

\frac{125}{5}

\frac{q - 1}{3} - \frac{q - 2}{4} = 2

\frac{3 ( x + 4 )}{2} = 8

3 x^{2} + 10 x

\frac{3 y}{4} - \frac{x}{3} + \frac{5 y}{6}

What are the solutions to the equation 4x^2=12 ?
The solutions to the equation 4x^2=12 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 4x^2=12
The zeros of 4x^2=12 are x=sqrt(3),x=-sqrt(3)