What are the solutions to the equation 21x^2=-12x ?

The solutions to the equation 21x^2=-12x are x=0,x=-4/7

Find the zeros of 21x^2=-12x

The zeros of 21x^2=-12x are x=0,x=-4/7

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21 x^{2} = - 12 x

x = 0, x = - \frac{4}{7}

Decimal Notation

x = 0, x = - 0.57142 \dots

Solution steps

21 x^{2} = - 12 x

Move

12 x

to the left side

21 x^{2} + 12 x = 0

Factor

21 x^{2} + 12 x : 3 x (7 x + 4)

3 x (7 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 7 x + 4 = 0

Solve

7 x + 4 = 0 : x = - \frac{4}{7}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{7}

\frac{2 - 4 i}{1 + 3 i}

\frac{3 x - 20}{2} = - 4

\frac{12 x ( x ^{3} - 2 )}{( x ^{3} + 1 ) ^{3}} \leq 0

f = 4 (3.9822) - (3.9822)^{2}

3 x^{2} - 42 = 0

What are the solutions to the equation 21x^2=-12x ?
The solutions to the equation 21x^2=-12x are x=0,x=-4/7
Find the zeros of 21x^2=-12x
The zeros of 21x^2=-12x are x=0,x=-4/7