What are the solutions to the equation (2x-1)^2=16 ?

The solutions to the equation (2x-1)^2=16 are x= 5/2 ,x=-3/2

Find the zeros of (2x-1)^2=16

The zeros of (2x-1)^2=16 are x= 5/2 ,x=-3/2

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(2 x - 1)^{2} = 16

x = \frac{5}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.5, x = - 1.5

Solution steps

(2 x - 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 16 : x = \frac{5}{2}

Solve

2 x - 1 = - 16 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{3}{2}

am - bm + an - bn

3 x^{2} + 5 x + 7 = 0

(3 y^{4})^{2}

\frac{1}{- \frac{2}{2}}

∣ 2 x - 5 ∣ + 2 > 5

What are the solutions to the equation (2x-1)^2=16 ?
The solutions to the equation (2x-1)^2=16 are x= 5/2 ,x=-3/2
Find the zeros of (2x-1)^2=16
The zeros of (2x-1)^2=16 are x= 5/2 ,x=-3/2