What is factor n^2-4n-5 ?

The solution to factor n^2-4n-5 is (n+1)(n-5)

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factor n^2-4n-5

factor

n^{2} - 4 n - 5

(n + 1) (n - 5)

Solution steps

n^{2} - 4 n - 5

Break the expression into groups

= (n^{2} + n) + (- 5 n - 5)

Factor out

n

from

n^{2} + n : n (n + 1)

Factor out

- 5

from

- 5 n - 5 : - 5 (n + 1)

= n (n + 1) - 5 (n + 1)

Factor out common term

n + 1

= (n + 1) (n - 5)

\frac{b ^{3} - 8}{b ^{2} - 9} \cdot \frac{b + 3}{b ^{2} + 2 b + 4}

\frac{x - 9}{8} = 6

8 b^{2} - 10 b + 3

x y + 2 y - x - 2

x^{2} - 5 x^{4}