What are the solutions to the equation -x^2+9x+7=0 ?

The solutions to the equation -x^2+9x+7=0 are x=-(-9+sqrt(109))/2 ,x=(9+sqrt(109))/2

Find the zeros of -x^2+9x+7=0

The zeros of -x^2+9x+7=0 are x=-(-9+sqrt(109))/2 ,x=(9+sqrt(109))/2

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- x^{2} + 9 x + 7 = 0

x = - \frac{- 9 + 109}{2}, x = \frac{9 + 109}{2}

Decimal Notation

x = - 0.72015 \dots, x = 9.72015 \dots

Solution steps

- x^{2} + 9 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

9^{2} - 4 (- 1) \cdot 7 = 109

x_{1, 2} = \frac{- 9 \pm 109}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 109}{2 ( - 1 )}, x_{2} = \frac{- 9 - 109}{2 ( - 1 )}

x = \frac{- 9 + 109}{2 ( - 1 )} : - \frac{- 9 + 109}{2}

x = \frac{- 9 - 109}{2 ( - 1 )} : \frac{9 + 109}{2}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 109}{2}, x = \frac{9 + 109}{2}

x^{2} + x + 1

\frac{x - 4}{x + 1} \geq 0

- 6 - (- 5)

1^{10}

(32 - 9) (32 + 9)

What are the solutions to the equation -x^2+9x+7=0 ?
The solutions to the equation -x^2+9x+7=0 are x=-(-9+sqrt(109))/2 ,x=(9+sqrt(109))/2
Find the zeros of -x^2+9x+7=0
The zeros of -x^2+9x+7=0 are x=-(-9+sqrt(109))/2 ,x=(9+sqrt(109))/2