What are the solutions to the equation -x^2+x+20=0 ?

The solutions to the equation -x^2+x+20=0 are x=-4,x=5

Find the zeros of -x^2+x+20=0

The zeros of -x^2+x+20=0 are x=-4,x=5

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- x^{2} + x + 20 = 0

x = - 4, x = 5

Solution steps

- x^{2} + x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 20}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 20 = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 ( - 1 )}, x_{2} = \frac{- 1 - 9}{2 ( - 1 )}

x = \frac{- 1 + 9}{2 ( - 1 )} : - 4

x = \frac{- 1 - 9}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = - 4, x = 5

(x + 1)^{2} - 36 y^{2}

- ∣ u ∣ < - 6

t = - 4.9 t^{2} + 16.3 t + 15

n - 2 > - 22

\frac{1}{4} x + 6 = 42

What are the solutions to the equation -x^2+x+20=0 ?
The solutions to the equation -x^2+x+20=0 are x=-4,x=5
Find the zeros of -x^2+x+20=0
The zeros of -x^2+x+20=0 are x=-4,x=5