What are the solutions to the equation 3x^2-16x=12 ?

The solutions to the equation 3x^2-16x=12 are x=6,x=-2/3

Find the zeros of 3x^2-16x=12

The zeros of 3x^2-16x=12 are x=6,x=-2/3

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3 x^{2} - 16 x = 12

x = 6, x = - \frac{2}{3}

Decimal Notation

x = 6, x = - 0.66666 \dots

Solution steps

3 x^{2} - 16 x = 12

Move

12

to the left side

3 x^{2} - 16 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 12) = 20

x_{1, 2} = \frac{- ( - 16 ) \pm 20}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 20}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 20}{2 \cdot 3}

x = \frac{- ( - 16 ) + 20}{2 \cdot 3} : 6

x = \frac{- ( - 16 ) - 20}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 6, x = - \frac{2}{3}

4 x (x + y) - x^{2}

2 x^{3} - 3 x^{2} - 3 x + 2

x^{2} = 3 x - 6

\frac{1}{5 ^{3}}

6 x + 6 < 2 x - 2

What are the solutions to the equation 3x^2-16x=12 ?
The solutions to the equation 3x^2-16x=12 are x=6,x=-2/3
Find the zeros of 3x^2-16x=12
The zeros of 3x^2-16x=12 are x=6,x=-2/3